科目9702-physicsPhysics Paper 4 — A Level Structured QuestionstopicsTopic 22 — Quantum PhysicsTopic 22 — Last Minute Summary本页总览考前速记 Last Minute Summary 核心公式 Key Formulas E=hf=hcλE = hf = \frac{hc}{\lambda}E=hf=λhc p=Ec=hλp = \frac{E}{c} = \frac{h}{\lambda}p=cE=λh hf=Φ+12mvmax2(Photoelectric effect)hf = \Phi + \frac12 mv_{\text{max}}^2 \quad \text{(Photoelectric effect)}hf=Φ+21mvmax2(Photoelectric effect) λ=hp(de Broglie)\lambda = \frac{h}{p} \quad \text{(de Broglie)}λ=ph(de Broglie) hf=E1−E2(Energy levels)hf = E_1 - E_2 \quad \text{(Energy levels)}hf=E1−E2(Energy levels) 常数 Memorise h=6.63×10−34h = 6.63 \times 10^{-34}h=6.63×10−34 J s e=1.60×10−19e = 1.60 \times 10^{-19}e=1.60×10−19 C 111 eV =1.60×10−19= 1.60 \times 10^{-19}=1.60×10−19 J c=3.00×108c = 3.00 \times 10^8c=3.00×108 m s−1^{-1}−1 me=9.11×10−31m_e = 9.11 \times 10^{-31}me=9.11×10−31 kg 考前 Checklist eV ↔ J 转换 (×1.60×10−19\times 1.60 \times 10^{-19}×1.60×10−19) nm → m (×10−9\times 10^{-9}×10−9) f0=Φ/hf_0 = \Phi/hf0=Φ/h (threshold frequency) Photon: quantum of electromagnetic radiation Work function: minimum energy to remove electron (from surface) Higher intensity → more photons → more photoelectrons → larger current Higher frequency → more energy per photon → larger EK,maxE_{K,\text{max}}EK,max de Broglie: λ=h/p\lambda = h/pλ=h/p, moving particle has wave nature Electron diffraction: evidence for wave nature of particles Discrete energy levels → line spectra