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考前速记

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考前 15 分钟阅读,重点回忆公式和易错点。

核心公式

Projectile Motion

x=ucosθty=usinθt12gt2y=xtanθgx22u2cos2θ\begin{aligned} x &= u\cos\theta \cdot t \\ y &= u\sin\theta \cdot t - \frac{1}{2}gt^2 \\ y &= x\tan\theta - \frac{gx^2}{2u^2\cos^2\theta} \end{aligned}

Equilibrium of Rigid Body

  • 力矩 M=r×F\mathbf{M} = \mathbf{r} \times \mathbf{F},大小 M=FdM = Fd
  • 平衡条件:Fx=0, Fy=0, M=0\sum F_x = 0,\ \sum F_y = 0,\ \sum M = 0

Circular Motion

a=v2r=rω2,F=mv2ra = \frac{v^2}{r} = r\omega^2,\quad F = m\frac{v^2}{r}

Hooke's Law

T=λxL,EPE=λx22LT = \frac{\lambda x}{L},\quad \text{EPE} = \frac{\lambda x^2}{2L}

Linear Motion Under Variable Force

F=ma=mdvdt=mvdvdxF = ma = m\frac{dv}{dt} = mv\frac{dv}{dx}

Momentum

m1u1+m2u2=m1v1+m2v2,e=v2v1u1u2m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2,\quad e = \frac{v_2 - v_1}{u_1 - u_2}

易错清单

问题注意事项
抛体最高点vy=0v_y = 0,但 vxv_x 不为零
刚体力矩使用垂直距离(不是斜边)
圆周运动最顶点速度最小值对应 mgmg 提供向心力
弹性绳松弛T=0T = 0x0x \leq 0,EPE = 0
变力方向注意正负号与运动方向的关系
斜碰分别沿法线和切线方向处理