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Parametric Equations — Mark Scheme Patterns

Mark Allocation Overview

Question TypeTotal MarksM marksA marksB marks
First derivative dydx\frac{dy}{dx}2–311–20
Second derivative d2ydx2\frac{d^2y}{dx^2}31–21–20
Parametric differentiation combined5230
Arc length5–62–330

Pattern: First Derivative (2–3 marks)

  • M1: Find dxdt\frac{dx}{dt} and dydt\frac{dy}{dt} correctly
  • A1: Correct dydx\frac{dy}{dx} expression (may be unsimplified)
  • A1: Correct simplified form (if required)
常见扣分

dydx\frac{dy}{dx} 未简化到最简形式,可能丢 A1。如 t22t\frac{t^2}{2t} 应简化为 t2\frac{t}{2}

Pattern: Second Derivative (3 marks, often part of a larger question)

  • M1: Differentiate dydx\frac{dy}{dx} with respect to tt
  • A1: Correct ddt(dydx)\frac{d}{dt}\left(\frac{dy}{dx}\right)
  • A1: Correct d2ydx2\frac{d^2y}{dx^2} (divide by dxdt\frac{dx}{dt})
评分标志

M1 仅给到"对 tt 求导"这一步。如果直接用 y¨x¨\frac{\ddot{y}}{\ddot{x}} 则不得分——必须展示除以 dxdt\frac{dx}{dt} 的步骤。

Pattern: Arc Length (5–6 marks)

  • M1: Find dxdt\frac{dx}{dt} and dydt\frac{dy}{dt}
  • M1: Form (dxdt)2+(dydt)2\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2
  • A1: Simplify integrand (e.g. 8(1cost)8(1-\cos t) or 16sin2(t/2)16\sin^2(t/2))
  • M1: Set up arc length integral L=(x˙2+y˙2)dtL = \int \sqrt{(\dot{x}^2 + \dot{y}^2)}\,dt
  • A1: Correct square root simplification
  • A1: Correct final answer

评分关键点

步骤得分点常见错误
dxdt\frac{dx}{dt}, dydt\frac{dy}{dt}M1导数计算错误
平方和M1漏项或展开错误
化简A1未用半角公式
积分设置M1积分变量写错
开方A1忽略绝对值
最终答案A1数值或代数错误

Follow-Through Rules

  • 如果 dxdt\frac{dx}{dt}dydt\frac{dy}{dt} 错一个,后续的 dydx\frac{dy}{dx}ft
  • 弧长问题中,平方和化简错则后续不得分
  • d2ydx2\frac{d^2y}{dx^2} 中,dydx\frac{dy}{dx} 的错可 ft,但方法必须正确