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Implicit Differentiation — Last Minute Summary

dydx\frac{dy}{dx} in 4 Steps

  1. Differentiate every term w.r.t. xx
  2. For yy-terms: multiply by dydx\frac{dy}{dx}
  3. For xyxy-terms: product rule y+xdydxy + x\frac{dy}{dx}
  4. Rearrange: collect dydx\frac{dy}{dx} terms, factor, divide

d2ydx2\frac{d^2y}{dx^2} in 3 Steps

  1. Differentiate dydx\frac{dy}{dx} w.r.t. xx (use quotient rule if fraction)
  2. Replace any dydx\frac{dy}{dx} with the expression from step 1
  3. Simplify using the original equation to get answer in xx, yy only

Tangent and Normal

  • Tangent: yy0=m(xx0)y - y_0 = m(x - x_0) where m=dydx(x0,y0)m = \frac{dy}{dx}\big|_{(x_0,y_0)}
  • Normal: yy0=1m(xx0)y - y_0 = -\frac{1}{m}(x - x_0) (if m0m \neq 0)

Common Derivatives

ddx(yn)=nyn1dydx\frac{d}{dx}(y^n) = n y^{n-1}\frac{dy}{dx}

ddx(siny)=cosydydx\frac{d}{dx}(\sin y) = \cos y\frac{dy}{dx}

ddx(ey)=eydydx\frac{d}{dx}(e^y) = e^y\frac{dy}{dx}

ddx(lny)=1ydydx\frac{d}{dx}(\ln y) = \frac{1}{y}\frac{dy}{dx}

ddx(xy)=y+xdydx\frac{d}{dx}(xy) = y + x\frac{dy}{dx}

Stationary Points

Set dydx=0\frac{dy}{dx} = 0 → solve simultaneously with original equation.

Trap Checklist

❌ Forgetting dydx\frac{dy}{dx} on yy-terms

❌ Product rule on xyxy: ddx(xy)=y+xdydx\frac{d}{dx}(xy) = y + x\frac{dy}{dx}, not just yy

d2ydx2\frac{d^2y}{dx^2} substitution: substitute dydx\frac{dy}{dx} before simplifying

❌ Using xx and yy from the wrong point